Create symlink to the final target of another symlink

Suppose a have a symlink named A

If I execute this:

ln B A -s

then B points to A, having created a chain of symlinks: B->A->some

Is there any option for ln to link directly to the final target, without writing it explicitly? to get B->some?

I would do that with readlink like this:

ln B $(readlink A -f) -s

But I think it should exist some option do it just with ln.