I have a SSD drive that is going bad. So I’ve run:
chkdisk /x/b d:
in an attempt to repair it by forcing the entire drive /b to be scanned, and remapped to bad-sectors to usable sectors.
The options /b and /x are described below and in this URL https://docs.microsoft.com/en-us/windows-server/administration/windows-commands/chkdsk
/b – Use with NTFS only. Clears the list of bad clusters on the volume and rescans all allocated and free clusters for errors. /b includes the functionality of /r. Use this parameter after imaging a volume to a new hard disk drive.
/r – Locates bad sectors and recovers readable information. The disk must be locked. /r includes the functionality of /f, with the additional analysis of physical disk errors.
/x – Forces the volume to dismount first, if necessary. All open handles to the drive are invalidated. /x also includes the functionality of /f.
So the question I have is: Does the /b option cause the drive to wear out more quickly (by relocating bad sectors)?
My belief is that if the /r scan and repair bad-sectors option was used, this would be OK because only sectors that couldn’t be read are moved to a new location and the bad-sector-list would be updated only if a new bad-sector were found.
But I’m not sure about the /b option.
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